如同上一篇解释http://blog.youkuaiyun.com/fzxy002763/article/details/7959555的一些基本概念,这里我们采用fibonacci做为基
根据zeckendorf定理,这里如果j>>(意思为远大于,至少大两个)k -> j>k+2,那么任何一个正整数都有唯一表示,不过在程序里面没有用到这个。
注意fibonacci作为基这没有重复项,基初始几个为0 1 2 3 5 8 13。。。。这样,不存在1 1的重复,需要注意,代码还是java的
import javax.print.DocFlavor.STRING;
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.io.IOException;
import java.io.StringWriter;
import java.math.*;
public class transform {
/**
* make by Edward.xu
* 9.8.2012 0:24
* small version 0.3
*/
// the O(finbonacciNumber.length()*n)
static JTextField deciamlField;
static JTextField finbonacciField;
static long decimal;
static long finbonacci;
static long decimalPrint;
static String decimalNumber;
static String finbonacciNumber;
// debug use
// it's a loop flag
static int i;
public static void main(String[] args) {
// TODO Auto-generated method stub
// print function,long time no to use java
// to write a kit
finbonacciNumber = new String();
decimalNumber = new String();
System.out.println("徐方鑫特制-超级小型机制转换器");
// create a frame which is the main panel
JFrame frame = new JFrame("徐方鑫设计-must");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
// the main panel
JPanel panel = new JPanel();
frame.add(panel);
// i like use the box.expecially the vertical box
Box mainBox = Box.createVerticalBox();
panel.add(mainBox);
// to prove my write
/*
JLabel verionLabel = new JLabel("Version 0.1");
JLabel schoolLabel = new JLabel("Master of must 2012");
JLabel nameLabel = new JLabel("Made by Edward.xu");
mainBox.add(verionLabel);
mainBox.add(schoolLabel);
mainBox.add(nameLabel);
*/
// the first box which tip this is decimal number
Box deciamlBox = Box.createHorizontalBox();
mainBox.add(deciamlBox);
JLabel deciamlLabel = new JLabel("Deciaml:");
deciamlField = new JTextField();
deciamlBox.add(deciamlLabel);
deciamlBox.add(deciamlField);
// the second box which tip this is finbonacci number
Box finbonacciBox = Box.createHorizontalBox();
mainBox.add(finbonacciBox);
JLabel finbonacciLabel = new JLabel("finbonacci:");
finbonacciField = new JTextField();
finbonacciBox.add(finbonacciLabel);
finbonacciBox.add(finbonacciField);
// the button start transform
Box buttonBox = Box.createHorizontalBox();
mainBox.add(buttonBox);
JButton decToBinButton = new JButton("10 to Fibonacci");
JButton binToDecButton = new JButton("Fibonacci to 10");
buttonBox.add(decToBinButton);
buttonBox.add(binToDecButton);
// the main function of the calculate
decToBinButton.addActionListener(new ActionListener()
{
public void actionPerformed(ActionEvent e1)
{
finbonacciNumber = "";
try{
decimalNumber = deciamlField.getText();
decimal = Long.parseLong(decimalNumber);
if(decimal > 1000) throw new Exception();
// main transform
// calculate the top bit
for(i=0 ; calFibonacci(i) < decimal ; i++);
if(calFibonacci(i) == decimal) i = i;
else if(calFibonacci(i) > decimal) i = i-1;
//System.out.print("i "+i);
// end calculate the tip bit
// that's notice i use the function
// like i can choice what bit is 1
// that change bit data to the number
// is too 2,but funny
// to use the function like change to the decimal
finbonacci = (long)Math.pow(10, i-1);
finbonacciNumber = String.valueOf(finbonacci);
finbonacciField.setText(finbonacciNumber);
// update the new decimal which had minus the top bit
decimal = decimal - calFibonacci(i);
//System.out.println(" the decimal least:"+decimal);
// warning because of the long limit
// add my lazy,it's time to go to bed
// so i won't to change it to the string
// that cause it's only can change the number
// below 1000
// even it can be solve , but i won't to do
while(decimal !=0)
{
// use the same function calculate the bit second
for(i=0 ; calFibonacci(i) < decimal ; i++);
if(calFibonacci(i) == decimal) i = i;
else if(calFibonacci(i) > decimal) i = i-1;
//System.out.print("i2 "+i);
decimal = decimal - calFibonacci(i);
//System.out.println(" the decimal least2:"+decimal);
finbonacci = finbonacci + (long)Math.pow(10, i-1);
finbonacciNumber = String.valueOf(finbonacci);
finbonacciField.setText(finbonacciNumber);
}
}catch(Exception ex1)
{
JOptionPane.showMessageDialog(null, "你是在填数字吗?(注意不要大于1000),这可以改良,但是我懒得改了,注意,转换为显示的时候为乘10,改良就直接按照字符11这样打印,不要用Long类型做保存,用string,这样添加就行了。。。挺晚了,想睡了,不改了");
}
}
});
binToDecButton.addActionListener(new ActionListener()
{
public void actionPerformed(ActionEvent e2)
{
try{
finbonacci = 0;
decimal = 0;
decimalPrint = 0;
finbonacciNumber = finbonacciField.getText();
finbonacci = Long.parseLong(finbonacciNumber);
// notice that's is decimalPrint
decimalPrint = finbonacci % 10;
for (int i = finbonacciNumber.length() - 1; i>0 ; i--)
{
// the calculate this bit
decimal = finbonacci / (long) (Math.pow(10, i)) ;
finbonacci = finbonacci - (finbonacci / (long) (Math.pow(10, i)))*(long) Math.pow(10, i);
// calculate
// different between -2 basement
// the 10 is act as calFibonacci(2),not calFinbonacci(1)
// it's must be warning
decimalPrint = decimalPrint + decimal * calFibonacci(i + 1);
//System.out.println("decimal:"+decimal+" i:"+i);
}
System.out.println("decimalPrint:"+decimalPrint);
//System.out.println(decimal);
decimalNumber = String.valueOf(decimalPrint);
deciamlField.setText(decimalNumber);
}catch(Exception ex1)
{
JOptionPane.showMessageDialog(null, "你是在填数字吗?");
}
}
});
// start the frame and panel,make it visible
frame.setSize(300,140);
frame.setVisible(true);
}
//that's to calculate the Fibonacci serials
public static long calFibonacci(int n)
{
long fibonacci_one,fibonacci_two;
fibonacci_one = 0;
fibonacci_two = 1;
for(int i = 0 ; i < n ; i++)
{
long temp;
// to simple is
// temp = b
// b = b + a
// a = temp
temp = fibonacci_two;
fibonacci_two = fibonacci_two + fibonacci_one ;
fibonacci_one = temp;
//System.out.println(" "+fibonacci_two+" ");
}
if(n == 0) return 0;
else if(n == 1) return 1;
else if(n == 2) return 2;
else return fibonacci_two;
}
}