const double EPS = 1e-10;
double calc(double n)
{
return;
}
double solve(double L, double R)
{
double M, RM;
while (L + EPS < R)
{
M = (L + R) / 2;
RM = (M + R) / 2;
if (calc(M) < calc(RM)) //计算最小值
R = RM;
else
L = M;
}
return R;
}