PAT 1005. Spell It Right (20)

最新推荐文章于 2024-05-17 16:45:04 发布

iteye_15379

最新推荐文章于 2024-05-17 16:45:04 发布

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本文介绍了一个简单的程序设计问题：将输入数字的各位数之和用英文单词形式输出。程序首先读取一个字符串形式的大整数，计算其各位数字之和，并将该和数转换为英文表示形式。

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Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10¹⁰⁰).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

#include<stdio.h>
#include<string.h> 
char number[100];
int reminder[10];
int main(){
                scanf("%s", &number);
                int i;
                int sum = 0;
                for (i=0;i<strlen(number);i++) 
                        sum += number[i] - '0';
//                printf("sum = %d\n", sum);
				if(sum == 0){
					printf("zero\n");
				}
				else {
					for(i=0; i < 10 && sum !=0; i++){
							reminder[i] = sum%10;
							sum /= 10;
//							printf("reminder[%d] = %d\n", i, reminder[i]);
					}
					for(i = i -1; i >=0; i--){
							print(reminder[i]);
							if(i != 0) printf(" ");
							else printf("\n");
					}
				}
        return 0;
}
 
void print(int number){
        switch(number){
        case 0: 
                printf("zero");
                break;
        case 1:
                printf("one");
                break;
        case 2: 
                printf("two");
                break;
        case 3:
                printf("three");
                break;
        case 4: 
                printf("four");
                break;
        case 5:
                printf("five");
                break;
        case 6: 
                printf("six");
                break;
        case 7:
                printf("seven");
                break;
        case 8: 
                printf("eight");
                break;
        case 9:
                printf("nine");
                break;
        }
}

NOTES:

1.string -- scanf("%s", &number);
2.sum += number[i] - '0';
3.注意边界case

4.string length -- #include<string.h> strlen(number);

5.http://beej.us/guide/bgc/output/html/multipage/scanf.html

scanf

h
The value to be parsed is a short int or short unsigned. Example: %hd or %hu.

l
The value to be parsed is a long int or long unsigned, or double (for %f conversions.) Example: %ld, %lu, or %lf.

L
The value to be parsed is a long long for integer types or long double for float types. Example: %Ld, %Lu, or %Lf.

6.max int: 2147483647
max long long 9223372036854775807