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日常错误
第二届南晓程序设计竞赛新年赛-外网dalao狂欢 个人总结问题 A: 集训队日常之JBB的烦恼时间限制: 1 Sec 内存限制: 32 MB提交: 402 解决: 235[提交][状态][讨论]题目描述JBB一直有个大大的烦恼。她总是认为自己的才能适合行政工作，不适合写代码，不敢考卓工班。但是又怕跟BigBaiZhou说了以后会收到原创 2017-12-21 08:21:29 · 529 阅读 · 0 评论 -
CF Playing With Strings
I. Playing With Stringstime limit per test 2.0 smemory limit per test 64 MBstandard outputDani and Mike are two kids ,They are playing games all day and when they don't find a game t...原创 2018-04-19 16:17:16 · 285 阅读 · 0 评论 -
CF Make Cents?
M. Make Cents?time limit per test6.0 smemory limit per test256 MBinputstandard inputoutputstandard outputEvery year, an elephant qualifies to the Arab Collegiate Programming Competition. He graduated ...原创 2018-04-25 08:45:47 · 236 阅读 · 0 评论 -
第四届趣味编程大赛 小国的游戏
小国的游戏Time Limit: 1 Sec Memory Limit: 64 MBSubmit: 91 Solved: 24[Submit][Status][Discuss]Description可怜的小国和小辉在双十一过后，吃饭都吃不起了，只能在吃饭时间玩会游戏来打发时间。可是时间久了之后，他们各种游戏都玩了一遍，所以他们两个打算合作出一个新奇的游戏。最终，他们决定先做四个纸箱，每个纸箱里...原创 2018-04-25 09:19:32 · 662 阅读 · 0 评论 -
Game
Game Time limit 1000 ms Memory limit262144 kB ...原创 2018-05-03 08:32:06 · 211 阅读 · 0 评论 -
Tic-Tac-Toe
Tic-Tac-Toe Kim likes to play Tic-Tac-Toe. Given a current state, and now Kim is going to take his next move. Please tell Kim if he can win the game in next 2 moves if both player are clever enough. ...原创 2018-05-03 08:37:39 · 624 阅读 · 0 评论 -
Linearization of the kernel functions in SVM
Linearization of the kernel functions in SVM SVM（Support Vector Machine）is an important classification tool, which has a wide range of applications in cluster analysis, commun...原创 2018-05-03 09:01:16 · 297 阅读 · 0 评论 -
Log Files
Log Files Nikolay has decided to become the best programmer in the world! Now he regularly takes part in various prog...原创 2018-05-03 15:27:03 · 324 阅读 · 0 评论 -
Marjar Cola
Marjar ColaMarjar Cola is on sale now! In order to attract more customers, Edward, the boss of Marjar Company, decides to launch a promotion: If...原创 2018-05-03 19:10:59 · 320 阅读 · 0 评论 -
HDU 1798 Tell me the area
Tell me the area Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64uDescription There are two circles in the plane (shown in the below picture),...原创 2018-04-19 16:03:15 · 218 阅读 · 0 评论 -
abs fabs fabsf 用法
int abs(int i); //处理int类型的取绝对值double fabs(double i); //处理double类型的取绝对值float fabsf(float i); //处理float类型的取绝对值还有些待学习的强大的函数，如：ssanf swap atof(这一类的函数);...原创 2018-04-19 15:41:42 · 2369 阅读 · 0 评论 -
HDU 1013 Digital Roots 九余定理
Digital Roots Time Limit: 1 Sec Memory Limit: 64 MBDescriptionThe digital root of a ...原创 2018-04-12 14:59:58 · 285 阅读 · 0 评论 -
Adding Reversed Numbers 数的反转
Adding Reversed NumbersTime Limit: 1 Sec Memory Limit: 64 MBSubmit: 300 Solved: 143[Submit][Status][Discuss]DescriptionThe Antique Comedians of Malidinesia prefer comedies to tragedies. Unfortunatel...原创 2018-02-18 16:49:00 · 593 阅读 · 0 评论 -
POJ 1007 DNA Sorting 多个数组代替结构体
DNA SortingTime Limit: 1 Sec Memory Limit: 64 MBSubmit: 327 Solved: 140[Submit][Status][Discuss]DescriptionOne measure of ``unsortedness'' in a sequence is the number of pairs of entries that are ou...原创 2018-02-19 21:10:16 · 280 阅读 · 0 评论 -
Codefroces194A Exams
H - ExamsTime Limit:2000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64uSubmit Status Practice CodeForces 194A DescriptionOne day the Codeforces round author sat exams. He had n exam...原创 2018-03-11 10:27:13 · 250 阅读 · 0 评论 -
SDUT 2886 Weighted Median
Weighted Median Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%lld & %lluDescriptionFor n elements x1, x2, ..., xn with positive integer weights w1, w2, ..., wn...原创 2018-03-30 15:25:22 · 249 阅读 · 0 评论 -
SDUT 3275 LCM的个数
LCM的个数 Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%lld & %lluDescription 对于我们来说求两个数的LCM（最小公倍数）是很容易的事，现在我遇到了一个问题需要大家帮助我来解决这问题，问题是：给你一个数n，然后统计有多少对(a&l...原创 2018-03-31 09:49:46 · 259 阅读 · 0 评论 -
Counting-out Rhyme 约瑟夫环
Counting-out Rhyme Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64uSubmit Status Practic...原创 2018-03-28 08:48:56 · 353 阅读 · 0 评论 -
CodeForces 939A（水题）
DescriptionAs you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are n planes on Earth, numbered from 1 to n, and the plane with numb...原创 2018-03-28 09:18:25 · 525 阅读 · 0 评论 -
POJ题目分类 [转]
大佬博客：传送门初期:一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. (5)构造法.(poj3295) (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996)二.图算法: (1)图的深度...转载 2018-06-29 16:44:45 · 286 阅读 · 0 评论