LeetCode | 136. Single Number

 

题目：

Given a non-empty array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Example 1:

Input: [2,2,1]
Output: 1

Example 2:

Input: [4,1,2,1,2]
Output: 4

 

代码：

class Solution {
public:
    int singleNumber(vector<int>& nums) {
        if(nums.size() == 1)
			return nums[0];
        int target = 0;
        for(int i = 0; i<nums.size(); i++)
            target ^= nums[i];
		return target; 
    }
};