题目:
Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.
Example 1:
Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac"
Output: true
Example 2:
Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc"
Output: false
代码:
class Solution {
public:
bool isInterleave(string s1, string s2, string s3) {
int len1 = s1.length(), len2 = s2.length(), len3 = s3.length();
if (len1 + len2 != len3)
return false;
vector<vector<bool>> dp(len1 + 1, vector<bool>(len2+1, false));
dp[0][0] = true;
for (int i = 1; i <= len1; i++)
{
dp[i][0] = dp[i - 1][0] && (s1[i - 1] == s3[i - 1]);
}
for (int i = 1; i <= len2; i++)
{
dp[0][i] = dp[0][i - 1] && (s2[i - 1] == s3[i - 1]);
}
for (int i = 1; i <= len1; i++)
{
for (int j = 1; j <= len2; j++)
{
dp[i][j] = (dp[i - 1][j] && s1[i - 1] == s3[i + j - 1]) || (dp[i][j - 1] && s2[j - 1] == s3[i + j - 1]);
}
}
return dp[len1][len2];
}
};