Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 10,1,2,7,6,1,5
and target 8
,
A solution set is:
[1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
class Solution(object):
def bfs(self, candidates, target, result, valuelist, start):
if target == 0 and valuelist not in result:
return result.append(valuelist)
for index in range(start, len(candidates)):
if target < candidates[index]:
return
self.bfs(candidates, target - candidates[index], result, valuelist + [candidates[index]], index + 1)
def combinationSum2(self, candidates, target):
"""
:type candidates: List[int]
:type target: int
:rtype: List[List[int]]
"""
candidates.sort()
result = []
self.bfs(candidates, target, result, [], 0)
return result