Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def mergeTwoLists(self, l1, l2):
"""
:type l1: ListNode
:type l2: ListNode
:rtype: ListNode
"""
dummyHead = head = ListNode(None)
while l1 and l2:
if l1.val < l2.val:
head.next = l1
l1 = l1.next
head = head.next
else:
head.next = l2
l2 = l2.next
head = head.next
if l1:
head.next = l1
if l2:
head.next = l2
return dummyHead.next

本文介绍了一种方法来合并两个已排序的链表,并通过拼接节点的方式创建一个新的排序链表。该方法使用了一个虚拟头节点简化边界条件处理。
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