201. Bitwise AND of Numbers Range Leetcode Python

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本文介绍了一种针对给定范围 [m, n]（0 ≤ m ≤ n ≤ 2147483647）内所有整数进行按位与运算的算法。通过迭代移位操作，该算法能够快速找到并返回整个范围内的按位与结果。以示例 [5, 7] 为例，最终输出为 4。此问题特别感谢 @amrsaqr 添加和创建所有测试案例。

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Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

Credits:
Special thanks to @amrsaqr for adding this problem and creating all test cases.

code is as follow:

class Solution:
    # @param m, an integer
    # @param n, an integer
    # @return an integer
    def rangeBitwiseAnd(self, m, n):
        i = 0
        while m != n:
            m = m >>1
            n = n >> 1
            i += 1
        return m << i