CF 4A Watermelon(水??!!)

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最新推荐文章于 2022-05-23 22:37:27 发布

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分类专栏： ACM_基础题(水题) CF_A ACM_HDU刷题录文章标签： CF4A Watermelon

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题目描述了Pete和Billy两位小朋友想要将买来的重量为w公斤的西瓜均匀分成偶数重量的两部分。输入是西瓜的重量w，输出是判断他们是否能实现这一目标。当西瓜重量为偶数且大于2时，他们可以将西瓜分为两个偶数重量的部分，否则不行。

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Watermelon

Time Limit: 1000ms

Memory Limit: 65536KB

This problem will be judged on CodeForces. Original ID: 4A
64-bit integer IO format: %I64d Java class name: (Any)

Submit Status Statistics Discuss

Type:

None

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

Input

The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

Output

Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

Sample Input

Input

Output

YES

Hint

For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

Source

Codeforces Beta Round #4 (Div. 2 Only)

题意:

两个人分一个西瓜,问两个人能否分到偶数!

首先,分之前必须是偶数，且要大于2

AC代码:

#include <iostream>
using namespace std;
int main()
{
    int n;
    while(cin>>n)
    {
        if(n>2&&n%2==0)
            cout<<"YES"<<endl;
        else
            cout<<"NO"<<endl;
    }
    return 0;
}