思路:
暴力随便%一下就好啦
然后注意-1的情况
C o d e Code Code:
#include <iostream>
#include <cstdio>
int a,k;
using namespace std;
int main ()
{
freopen("num.in","r",stdin);
freopen("num.out","w",stdout);
scanf ("%d",&a);
for(int i = 10000; i < 30001; i++)
if((i / 100) % a == 0 && (i / 10 - i / 10000 * 1000) % a == 0 && (i % 1000) % a == 0){k++; printf ("%d\n", i);}//暴力
if(!k)printf("-1");//-1
}