// 剑指offer 面试题50 树中两个节点的最低公共祖先
#include <iostream>
#include <list>
#include <vector>
using namespace std;
struct TreeNode
{
char value;
vector<TreeNode*> m_vChildren;
TreeNode(char v) : value(v) {}
};
bool GetNodePath(TreeNode* pRoot, TreeNode* pNode, list<TreeNode*>& path)
{
if(pRoot == pNode)
return true;
path.push_back(pRoot);
bool found = false;
vector<TreeNode*>::iterator i = pRoot->m_vChildren.begin();
while(!found && i < pRoot->m_vChildren.end())
{
found = GetNodePath(*i, pNode, path);
++i;
}
if(!found)
path.pop_back();
return found;
}
TreeNode* GetLastCommonNode(const list<TreeNode*>& path1, const list<TreeNode*>& path2)
{
list<TreeNode*>::const_iterator iterator1 = path1.begin();
list<TreeNode*>::const_iterator iterator2 = path2.begin();
TreeNode* pLast = NULL;
while(iterator1 != path1.end() && iterator2 != path2.end())
{
if(*iterator1 == *iterator2)
pLast = *iterator1;
iterator1++;
iterator2++;
}
return pLast;
}
TreeNode* GetLastCommonParent(TreeNode* pRoot, TreeNode* pNode1, TreeNode* pNode2)
{
if(pRoot == NULL || pNode1 == NULL || pNode2 == NULL)
return NULL;
list<TreeNode*> path1;
list<TreeNode*> path2;
GetNodePath(pRoot, pNode1, path1);
GetNodePath(pRoot, pNode2, path2);
return GetLastCommonNode(path1, path2);
}
void Test1()
{
TreeNode* pRoot = new TreeNode('A');
TreeNode* pNodeB = new TreeNode('B');
TreeNode* pNodeC = new TreeNode('C');
pRoot->m_vChildren.push_back(pNodeB);
pRoot->m_vChildren.push_back(pNodeC);
TreeNode* pNodeD = new TreeNode('D');
TreeNode* pNodeE = new TreeNode('E');
pNodeB->m_vChildren.push_back(pNodeD);
pNodeB->m_vChildren.push_back(pNodeE);
TreeNode* pNodeF = new TreeNode('F');
TreeNode* pNodeG = new TreeNode('G');
pNodeD->m_vChildren.push_back(pNodeF);
pNodeD->m_vChildren.push_back(pNodeG);
TreeNode* pNodeH = new TreeNode('H');
TreeNode* pNodeI = new TreeNode('I');
TreeNode* pNodeJ = new TreeNode('J');
pNodeE->m_vChildren.push_back(pNodeH);
pNodeE->m_vChildren.push_back(pNodeI);
pNodeE->m_vChildren.push_back(pNodeJ);
TreeNode* pLastCommon = GetLastCommonParent(pRoot, pNodeF, pNodeG);
cout << pLastCommon->value << endl;
}
int main()
{
Test1();
return 0;
}
剑指offer 面试题50 树中两个节点的最低公共祖先
最新推荐文章于 2025-03-27 11:37:48 发布