POJ2406 Power Strings_given two strings a and b we define a*b to be thei-优快云博客

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Description

Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer is defined in the normal way: a^0 = "" (the empty string) and a^(n+1) = a*(a^n).

Input

Each test case is a line of input representing s, a string of printable characters. The length of s will be at least 1 and will not exceed 1 million characters. A line containing a period follows the last test case.

Output

For each s you should print the largest n such that s = a^n for some string a.

Sample Input

abcdaaaaababab.

Sample Output

#include<iostream>#include <cstdio>#include <cstdlib>#include <cstring>using namespace std;char str [1000010];      int  next[1000010];int getnext(){    int i=0,j=-1,len;    next[0]=-1;    while(str[i])    {        if(j==-1||str[i]==str[j])        {            i++;            j++;            next[i]=j;        }        else           j=next[j];    }    len=strlen(str);    i=len-j;    if(len%i==0)         return len/i;    else         return 1;}int main(){    while( gets( str), str[0]!= '.' )    printf("%d\n", getnext() );    return 0;}