1.31代码练习

1

#include <stdio.h>

long long Sum() {
    long long sum = 0;

    for (int i = 1; i <= 100; i++) {
        if (i % 2 == 1) {
            // 奇数，计算平方并累加
            sum += (long long)i * i;
        } else {
            // 偶数，计算立方并累加
            sum += (long long)i * i * i;
        }
    }

    return sum;
}

int main() {
    long long result = Sum();
    printf("1~100中奇数的平方与偶数的立方的和为: %lld\n", result);

    return 0;
}

2

#include <stdio.h>

int cal(int m, int n) {
    int cost = 0;
    int sets = (m < n) ? m : n; // 计算可以组成多少套

    // 成套购买的费用
    cost += sets * 120;

    // 剩余的上衣和裤子单独购买
    cost += (m - sets) * 59;
    cost += (n - sets) * 70;

    return cost;
}

int main() {
    int m, n;
    printf("请输入购买的上衣数量 (m): ");
    scanf("%d", &m);
    printf("请输入购买的裤子数量 (n): ");
    scanf("%d", &n);

    int sum = cal(m, n);
    printf("总费用为: %d 元\n", sum);

    return 0;
}