Edward, a poor copy typist, is a user of the Dvorak Layout. But now he has only a QWERTY Keyboard with a broken Caps Lock key, so Edward never presses the broken Caps Lock key. Luckily, all the other keys on the QWERTY keyboard work well. Every day, he has a lot of documents to type. Thus he needs a converter to translate QWERTY into Dvorak. Can you help him?
The QWERTY Layout and the Dvorak Layout are in the following:
The QWERTY Layout |
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|
The Dvorak Layout |
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|
Input
A QWERTY document Edward typed. The document has no more than 100 kibibytes. And there are no invalid characters in the document.
OutputThe Dvorak document.
Sample InputJgw Gqm Andpw a H.soav Patsfk f;doe Nfk Gq.d slpt a X,dokt vdtnsaohe Kjd yspps,glu pgld; aod yso kd;kgluZ 1234567890 `~!@#$%^&*()}"']_+-=ZQqWEwe{[\| ANIHDYf.,bt/ ABCDEFuvwxyzSample Output
Hi, I'm Abel, a Dvorak Layout user. But I've only a Qwerty keyboard. The following lines are for testing: 1234567890 `~!@#$%^&*()+_-={}[]:"'<>,.?/\| ABCDEFuvwxyz AXJE>Ugk,qf;
//第一步查找map,如果没有,转为小写字母再进行查找,此时如果没有,判断两种特殊情况,否则原样输出
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<string>
#include<map>
#include<iostream>
using namespace std;
const int maxn = 1100000;
char str[maxn];
map<string,int>id;
int main()
{
int i,j;
string s,s2;
id["_"] = '{';
id["-"] = '[';
id["+"] = '}';
id["="] = ']';
id["Q"] = '"';
// id["q"] = ''';
id["W"] = '<';
id["w"] = ',';
id["E"] = '>';
id["e"] = '.';
id["R"] = 'P';
id["T"] = 'Y';
id["Y"] = 'F';
id["U"] = 'G';
id["I"] = 'C';
id["O"] = 'R';
id["P"] = 'L';
id["{"] = '?';
id["["] = '/';
id["}"] = '+';
id["]"] = '=';
id["S"] = 'O';
id["D"] = 'E';
id["F"] = 'U';
id["G"] = 'I';
id["H"] = 'D';
id["J"] = 'H';
id["K"] = 'T';
id["L"] = 'N';
id[":"] = 'S';
id[";"] = 's';
// id["""] = '_';
id["'"] = '-';
id["Z"] = ':';
id["z"] = ';';
id["X"] = 'Q';
id["C"] = 'J';
id["V"] = 'K';
id["B"] = 'X';
id["N"] = 'B';
id["<"] = 'W';
id[","] = 'w';
id[">"] = 'V';
id["."] = 'v';
id["?"] = 'Z';
id["/"] = 'z';
while(gets(str)!=NULL)
{
s2.clear();
for(i = 0; str[i]!='\0'; i ++)
{
s.clear();
s = str[i];
if(id.count(s))
{
s2 += id[s];
}
else
{
if(str[i] == 'q')//判断特殊字符
{
s = str[i]-74;
s2 += s;
}
else if(str[i]>='a'&&str[i]<='z')//如果有小写字母
{
s = str[i]-32;//转化为大写进行查找
if(id.count(s))//找到则按小写存入
{
s = id[s]+32;
s2 += s;
}
else//找不到映射则原样存入
{
s = str[i];
s2 += s;
}
}
else if(str[i] == 34)//特判特殊字符
{
s = '_';
s2 += s;
}
else//其余情况原样存入
{
s = str[i];
s2 += s;
}
}
}
cout<<s2<<endl;
}
return 0;
}