大体来看,程序主要流程为这么几步
1. 将得到的字符串进行去空格处理。
2. 将第1步得到的字符串(此为中缀形式)转换为逆波兰式(后缀式)
3. 将第2步得到的逆波兰式(RPN)进行计算,求出结果并输出。
代码:
#include <iostream>
#include <map>
#include <stack>
#include <string>
#include <vector>
using namespace std;
#define MAX 1024
int queryPriority(char c)
{
if(c=='@')
return MAX+1;
if(c=='#')
return MAX+2;
if(c=='$')
return MAX+3;
if(c=='&')
return MAX+4;
return 0;
}
//√√√一出字符串中的空格
string removespace(string input)
{
string withoutspace;
int i=0;
int len=input.length();
for(i=0;i<len;i++)
{
if(input[i]!=' ')
withoutspace.append(1,input[i]);
}
return withoutspace;
}
//√√√将字符串转化为逆波兰表达式【从左向右扫描】
vector<int> convertToRPN(string inputStr)//转化成逆波兰表达式
{
int i=0;
int len=inputStr.length();
vector<int> RPN2;
stack<char> operatorstack;
int autonumber=0;
for(i=0;i<len;i++)
{
if(inputStr[i]>='0' &&inputStr[i]<='9')
autonumber=autonumber*10+inputStr[i]-'0';//操作数
else//操作符
{
RPN2.push_back(autonumber);
autonumber=0;
while(1)
{
if(operatorstack.empty()==true || queryPriority(operatorstack.top())>queryPriority(inputStr[i]))
{
operatorstack.push(inputStr[i]);
break;
}
else
{
RPN2.push_back(queryPriority(operatorstack.top()));
operatorstack.pop();
}
}
}
}
RPN2.push_back(autonumber);
while(operatorstack.empty()==false)//弹出栈内操作符
{
RPN2.push_back(queryPriority(operatorstack.top()));
operatorstack.pop();
}
return RPN2;
}
int march(int num1,int num2,int operate)
{
switch (operate)
{
case MAX + 1: //'@':
return (num1 - 1) * (num2 + 1);
case MAX + 2: //'#':
return (2 * num1 + 5) * (3 * num2 + 60);
case MAX + 3: //'$':
return (num1 + 1) * (2 * num1 + 3) * (num2 - 1) * (2 * num2 - 3);
case MAX + 4: //'&':
return ((num1 + num2 + 1) * (num2 - 9) + (num1 + 7) / (num2 - 8));
default:
return 0;
}
}
int calcRPN(vector<int> inputRPN)//计算逆波兰表达式的值
{
stack<int> numberstack;
int i=0;
int temp;
int num1=0,num2=0;
int len=inputRPN.size();
for(i=0;i<len;i++)
{
temp=inputRPN[i];
if(temp<MAX+1)//操作数
{
numberstack.push(temp);
}
else
{
num1=numberstack.top();
numberstack.pop();
num2=numberstack.top();
numberstack.pop();
numberstack.push(march(num2,num1,temp));
}
}
return numberstack.top();
}
int main()
{
string s;
getline(cin,s);
string news=removespace(s);
vector <int> t;
t=convertToRPN(news);
int i=0;
int len=t.size();
for(i=0;i<len;i++)
{
cout<<t[i]<<" ";
}
cout<<endl;
int num=calcRPN(t);
cout<<num<<endl;
return 0;
}