wash card （lua实现）

function wash(a)

local times = 52

local ranIndex = 0

local cIndex = 0

for i = 1,52 do

   a[i] = i

end

for i = 1,times do

   ranIndex = math.random(1,52)

   cIndex = math.mod(i,53)

   if cIndex ~= ranIndex then

    a[cIndex],a[ranIndex] = a[ranIndex],a[cIndex]

   end

end

end

--print(math.mod(15,11))

function isqual(a) -- 判断如果有两个相同元素则返回相同元素的值

for i = 1,52 do

   if i > 1 then

    for j = 1,i - 1 do

     if a[i] == a[j] then

      return '重复的元素是' .. a[i]

     end

    end

   end

end

return "good"

end

poker ={}

wash(poker)

for i = 1,52 do

print(poker[i])

end

print(isqual(poker))