推推就出来了
#include <bits/stdc++.h>
using namespace std;
int main()
{
double s;
double pi = acos(-1);
cin >> s;
double r2 = s/(4*pi);
double ninev2 = s*s*r2-2*s*pi*r2*r2;
cout << fixed << setprecision(6) << sqrt(ninev2/9) << endl;
return 0;
}