Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
Update (2015-02-10):
The signature of the C++ function had been updated. If you still see your function signature accepts a const char * argument, please click the reload button to reset your code definition.
解答:
这是二刷时的结果了,我自己做出来了,找不到之前的博客文章了,就重新写一下。感觉这些testcase 有点变态,但是可以作为参考吧。
比如+-2
0a123
0 123
等等
class Solution {
public:
int myAtoi(string str) {
long long result=0;
int len=str.size();
int sign=1;
bool mark=false;
int i=0;
for(;i<len;i++)
{
if(str[i]==' ') continue;
else break;
}
for(;i<len;i++)
{
if(str[i]=='-'){if(mark==true)return false;else{sign=-1;mark=true;}continue;}
if(str[i]=='+'){if(mark==true)return false;else mark=true;continue;};
if(str[i]<='9'&&str[i]>='0')
{
result=result*10+str[i]-'0';
if(sign*result>=INT_MAX) return INT_MAX;
if(sign*result<=INT_MIN) return INT_MIN;
}
else
return sign*result;
}
return sign*result;
}
};