Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
这道题我是先把树变成一排序列,再比较相同与否,代码如下:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
void dfs(TreeNode*root,vector<int>&que) {
if(root == NULL){
que.push_back(0);
return;
}
que.push_back(root->val);
dfs(root->left,que);
dfs(root->right,que);
}
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
vector<int>p_que,q_que;
dfs(p,p_que);
dfs(q,q_que);
if(p_que.size() != q_que.size()) return false;
for(int i = 0; i < p_que.size(); i++){
if(p_que[i] != q_que[i]) return false;
}
return true;
}
};

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