hdu 5479 Scaena Felix 枚举

Scaena Felix

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 517    Accepted Submission(s): 223

Problem Description

Given a parentheses sequence consist of '(' and ')', a modify can filp a parentheses, changing '(' to ')' or ')' to '('.

If we want every not empty <b>substring</b> of this parentheses sequence not to be "paren-matching", how many times at least to modify this parentheses sequence?

For example, "()","(())","()()" are "paren-matching" strings, but "((", ")(", "((()" are not.

 

Input

The first line of the input is a integer  T , meaning that there are  T  test cases.

Every test cases contains a parentheses sequence  S  only consists of '(' and ')'.

1≤|S|≤1,000 .

 

Output

For every test case output the least number of modification.

 

Sample Input

  

   3
()
((((
(())
  

 

Sample Output

  

   1
0
2
  

 

Source

BestCoder Round #57 (div.2)

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
using namespace std;
#define maxn 1002
char w[maxn];
int num[maxn];

int main(){
    int t;
    scanf("%d",&t);
    while(t--){
        scanf("%s",w);
        int len = strlen(w);
        for(int i = 0;i < len; i++)
            if(w[i] == ')') num[i] = 0;
            else num[i] = 1;
        for(int i= 1;i < len; i++)
            num[i] = num[i]+num[i-1];
        int ans = len-num[len-1];
        for(int i = 0 ;i < len ;i++){
            ans = min(ans,num[i]+len-1-i-num[len-1]+num[i]);
        }
        printf("%d\n",ans);
    }
    return 0;
}