K&R C Exercise 1-22 Solution

最新推荐文章于 2019-07-24 22:34:17 发布

原创最新推荐文章于 2019-07-24 22:34:17 发布 · 696 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#c #character #fold #tabs #input

C/C++ 同时被 2 个专栏收录

55 篇文章

订阅专栏

K&R C Solutions

18 篇文章

订阅专栏

本文介绍了一个使用C语言编写的程序，该程序可以将长输入行根据指定的列数进行折叠，确保每行不超过预定义的最大列数。当达到最大列数时，程序会查找最后一个非空白字符并在此处换行。

/*
 * Exercise 1-22 Write a program to "fold" long input lines into
 * two or more shorter lines after the last non-blank character 
 * that occurs before the n-th column of input. Make sure your 
 * program does something intelligent with very long lines, and 
 * if there are no blanks or tabs before the specified column.
 * 
 * fduan, Dec. 12, 2011
 */

#include <stdio.h>

#define MAX_COL 10

int main()
{
	int c, i;
	char line[MAX_COL + 1] = { '\0' };
	
	i = 0;
	while( ( c = getchar() ) != EOF )
	{
		line[i++] = c;
		if( i == MAX_COL )
		{
			line[i--] = '\0';
			while( line[i] == ' ' || line[i] == '\t' )
				--i;
			line[i+1] = '\0';
			printf( "%s\n", line );
			i = 0;
		}
	}

	return 0;
}