List of problems to be solved

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#遗留问题目录

本文汇总了多个经典ACM算法题目，包括但不限于卷积和dp、打怪兽dp、字符串数量计算、走格子问题、次小生成树、斯坦纳树等。涉及动态规划、数据结构、数论及组合数学等多个领域。
[Notes] Introduction to The Design and Analysis of Algorithms from Anany Levitin
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[Notes] Introduction to The Design and Analysis of Algorithms from Anany Levitin1. Introduction1.1 What is an Algorithm?Greatest Common Divisor 1. Introduction 1.1 What is an Algorithm? Important poin...
Problems to be solved in ROS
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Run the python file in the Terminal and it shows: [rosrun] Couldn't find executable named xxx.py [rosrun] Found the following, but they're either not files, [rosrun]or executable: [rosrun]/home/***/*...
Problem List
Coldplay
09-15 493
2016 Dalin ACM 1002 Different GCD Subarray Query 1006 Football Games  1007 Friends and Enemies  1008 Function  1009 Sparse Graph 1010 Weak Pair
List of Problems to be Solved
weixin_34096182的博客
12-05 663
线段树专题 51nod 1593 公园晨跑 1199 Money out of Thin Air 1364 最大字典序排列 1766 树上的最远点对 1494 选举拉票 1781 Pinball 1571 最近等对 DP专题 51nod 字符串的数量 同V2 字符串的数量 V2 DP+矩阵乘法优化 字符串的数量 V3 幸运数 记忆化搜索 刷题BZOJ（Usaco） 1.【bzoj1597】[Usa...
17、Decidability of Optimization Problems in XML Query and Database Operations
seed的博客
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This blog explores the decidability of optimization problems in XML queries and database operations, offering insights into formal definitions, decision algorithms, and computational complexity. It covers practical examples and advanced topics like handlin
cannot be cast to android.widget.edittext,android.widget.Button cannot be cast to android.widget.Edi...
weixin_29119033的博客
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问题Developing my first Android calculator application, I succeeded in updating a TextView in a new activity by passing the answer via an intent, but this requires the user to hit Back to perform anothe...
how to find list of possible words from letter matrix
screaming的博客
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How to find list of possible words from a letter matrix [Boggle Solver] up vote338down votefavorite 274 Lately I have been playing a game on my iPhone called Scram
Linked List Cycle Problems
Bo Yang's Blog
09-14 1854
Linked List Cycle Problems: http://bo-yang.github.io/2014/07/13/linked-list-cycle
nltk - problems solved
nciaebupt
04-20 2242
1. Installation http://www.nltk.org/download The numpy and yaml need be installed first, all the three modules are installed from source. That's quite easy to install these modules, just download
The team Test just finished an exciting JB/ICPC competition. They are eager to know their ranking, but the board has been closed. So they can only guess their ranking by observing the submissions of other teams. Now let’s briefly introduce the rules of ranking. Each team has two statistics: the number of solved problems and penalty time. All teams are ranked according to their numbers of solved problems. If the numbers of solved problems of two different teams are equal, then they are ranked according to the penalty time. Each time a team passes a problem, the number of solved problems +1, and the time (in minutes) elapsed from the beginning of the competition is added to their penalty time. If a team has multiple submissions, each of the failed submissions will result in a 20 added to their penalty time. At the time when the competition lasts for four hours, the board will stop updating. In other words, the board is "frozen". After that, you can only see the submission status of other teams (the number of attempts, the time of the last submission), but you cannot see whether those submissions are accepted or not. In addition, the competition lasts for five hours in total. In particular, all teams will not submit solutions to the problem after getting an "Accepted". If two teams have the same number of solved problems and penalty time, then they are ranked the same. Please help the team Test guess the highest and lowest rankings they can reach based on the current board. The input contains several test cases, and the first line contains a positive integer indicating the number of test cases, . For each test case, the first line is a positive integer indicating the number of other teams, where . Then for each team, the first line are two integers and , where indicating the number of solved problems and indicating the penalty time of this team. The second line contains an integer indicating the submissions of problems of this team after the board is frozen. Then following lines, each line contains two positive integers and indicating the time of the last submission and the submit times of a problem of this team. Finally there is one line contains two integers and indicating the number of solved problems and the penalty time of the team Test. For each test case, output a line containing two positive integers indicating the highest and lowest rankings of the team Test. 输入样例 1 1 1 30 1 250 2 1 20 输出样例 1 2
最新发布
12-19
According to problem: “If two teams have the same number of solved problems and penalty time, then they are ranked the same.” So ranking rule: - Sort by solved ↓, penalty ↑ - Teams with identical...
The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line contains 3 positive integers, N (≤10 4 ), the total number of users, K (≤5), the total number of problems, and M (≤10 5 ), the total number of submissions. It is then assumed that the user id's are 5-digit numbers from 00001 to N, and the problem id's are from 1 to K. The next line contains K positive integers p[i] (i=1, ..., K), where p[i] corresponds to the full mark of the i-th problem. Then M lines follow, each gives the information of a submission in the following format: user_id problem_id partial_score_obtained where partial_score_obtained is either −1 if the submission cannot even pass the compiler, or is an integer in the range [0, p[problem_id]]. All the numbers in a line are separated by a space. Output Specification: For each test case, you are supposed to output the ranklist in the following format: rank user_id total_score s[1] ... s[K] where rank is calculated according to the total_score, and all the users with the same total_score obtain the same rank; and s[i] is the partial score obtained for the i-th problem. If a user has never submitted a solution for a problem, then "-" must be printed at the corresponding position. If a user has submitted several solutions to solve one problem, then the highest score will be counted. The ranklist must be printed in non-decreasing order of the ranks. For those who have the same rank, users must be sorted in nonincreasing order according to the number of perfectly solved problems. And if there is still a tie, then they must be printed in increasing order of their id's. For those who has never submitted any solution that can pass the compiler, or has never submitted any solution, they must NOT be shown on the ranklist. It is guaranteed that at least one user can be shown on the ranklist. Sample Input: 7 4 20 20 25 25 30 00002 2 12 00007 4 17 00005 1 19 00007 2 25 00005 1 20 00002 2 2 00005 1 15 00001 1 18 00004 3 25 00002 2 25 00005 3 22 00006 4 -1 00001 2 18 00002 1 20 00004 1 15 00002 4 18 00001 3 4 00001 4 2 00005 2 -1 00004 2 0 Sample Output: 1 00002 63 20 25 - 18 2 00005 42 20 0 22 - 2 00007 42 - 25 - 17 2 00001 42 18 18 4 2 5 00004 40 15 0 25 - C语言
12-17
#define MAX_PROBLEMS 6 typedef struct { int id; int total; int perfect; int grades[MAX_PROBLEMS]; int shown; } User; // 比较函数，用于 qsort int compare(const void *a, const void *b) { User *...
Schaum's Outline of Mathematica and the wolfram language 2019
04-12
and solved problems are short and to the point. Comments have been included, where appropriate, to clarify what might be confusing to the reader. The reader is encouraged not only to replicate the ...
PAT-天梯赛习题集-L3-014-周游世界
逐梦者
03-29 1913
ACM模版描述题解说实在的，这道题我没有完全解决，所以写这个博客不是为了帮助别人解决这个问题，而是希望有朋友帮我找到我的 bug，我找了大半天也没有找到问题所在，30分只得了19分，尴尬症犯了。为了方便大神们看我的代码，我先写一下自己的思路，这里我用的 Dijkstra 的队列+邻接表（堆）优化解法，多标签搜索，除了基础的距离 dist[]、vis[]，我又开了三个标签，pre[]：存储父节点，记录
通过若干次 rand() 使得随机数的和超过 RAND_MAX 的随机次数的期望
逐梦者
11-11 1466
最近看到一个代码，感觉十分有趣，MarkMarkMark 一下，来源不太清楚了。 首先说一下代码的功能：通过若干次随机使得随机数的和超过 RAND_MAXRAND\_MAXRAND_MAX，求这个随机次数的期望。 代码里通过 1e81e81e8 次操作，最后求随机次数的平均值的方法来得到这个期望。 #include <stdio.h> #include <stdlib.h>...
51Nod-1409-加强版贪吃蛇
逐梦者
06-23 1381
ACM模版描述 题解这个题是我在51Nod 上 AC 的第 300300 道题，尽管我并没有真正的、彻底的解决这道题……这个问题是一个 dp，如果不存在传送的问题，那么这个题就是一个十分水的题，一个地宫探宝问题的些微强化而已，然而，这里因为传送的问题，导致这里有一种重复覆盖的情况我无法解决，那就是一列循环了一周后的重复覆盖，据悉，这个情况 51 官方设置了第 21 组数据进行测试，可能这个是后来加
51Nod-1198-字符串的数量 V3
逐梦者
10-16 1251
ACM模版描述题解这道题好阔怕，在V1的讨论区有最牛逼的题解，Orz！！！虽然有题解，有代码，可是由于代数还没有学，所以对部分有些懵逼，先Mark一下，过一阵子能力有所提升后好好瞅瞅喽……提供两份代码，代码Two相比代码One多了一个预处理，针对多组数据可以提高很多效率！！！代码One：#include <stdio.h>typedef long long ll;const int MAXN = 6
51Nod-1607-卷积和
逐梦者
10-01 1071
ACM模版描述题解虽然不想说，但是还是不得不说，这道题我真的不会，看题解也没有什么觉悟……感觉自己要废了~~~看了一个大牛的代码，也是似懂非懂，暂且贴出大牛的代码，题解可以去大牛的链接看，我需要等到自己的造诣再稍微提升些才能搞定这道题了！Miracle_ma的博客>>>http://blog.youkuaiyun.com/miracle_ma/article/details/52170330代码#include
51Nod-1670-打怪兽
逐梦者
10-01 851
ACM模版描述题解一道十分不错的dp，越发的感觉我的dp好垃圾啊~~~关键是递推思维。官方题解：本题的关键点是发现如果我能在第i轮打败怪物j，那么我一定能在第i+1轮打败怪物j(前提是我还活着)。 因此我们可以通过递推来做这题。 令dp[i]表示第i轮我仍然存活时的方案综述，这里lyk的能量也必然为i。 显然dp[0]=n!。因为不管怎么排列，第0轮总是能存活的。 找到那些可以打败的怪物数量
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