三天打渔两天晒网（python）

#DayDayUp.py
#数学运算的模块
def dayup(df):
    dayup = 1
    for i in range(365):
        if i % 5 >= 3:
            dayup = dayup*0.999
        else:
            dayup = dayup*(1+df)
    return dayup
 
print('一年后努力的结果为{:.3f}'.format(dayup(0.001)))