#include <stdio.h> #include <cstring> #include <iostream> #define mod 1000000000 using namespace std; typedef long long LL; LL a[4][4],tmp[4][4],ans[4][4]; void mul(LL a[][4],LL b[][4]) { for(int i=1; i<=4; i++) for(int j=1; j<=4; j++) { tmp[i][j]=0; for(int k=1; k<=4; k++) tmp[i][j]+=a[i][k]*b[k][j]; if(tmp[i][j]>=mod) tmp[i][j]%=mod; } memcpy(a,tmp,sizeof(tmp)); } void pow(LL ans[][4],LL b[][4],int n) { memset(ans,0,sizeof(ans)); for(int i=1; i<=3; i++) ans[i][i]=1; while(n) { if(n&1) mul(ans,b); mul(b,b); n>>=1; } } int main() { int p,q,a1,a2; while(scanf("%d%d",&p,&q)==2) { if(p==0&&q==0) break; memset(a,0,sizeof(a)); a[1][1]=a[1][2]=a[2][1]=a[3][1]=a[3][3]=1; p--; if(p==0) a1=1; else { memset(ans,0,sizeof(ans)); pow(ans,a,p); a1=(ans[3][1]+ans[3][2]+ans[3][3])%mod; } if(q==0) a2=1; else { memset(ans,0,sizeof(ans)); memset(a,0,sizeof(a)); a[1][1]=a[1][2]=a[2][1]=a[3][1]=a[3][3]=1; pow(ans,a,q); a2=(ans[3][1]+ans[3][2]+ans[3][3])%mod; } printf("%d\n",(a2-a1+mod)%mod); } return 0; }
hoj 2060 Fibonacci Problem Again
最新推荐文章于 2017-09-14 20:26:28 发布