C# to POST HTTP with XML

最新推荐文章于 2025-05-31 16:41:34 发布

转载最新推荐文章于 2025-05-31 16:41:34 发布 · 944 阅读

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#c# #stream #credentials #null #string #exception

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本文深入探讨了HTTP POST请求的创建、发送、接收过程，包括设置URL、认证、请求方法、头信息、数据写入及响应处理。通过示例展示了如何使用C#进行HTTP POST请求，包括设置数据格式、头信息、读取服务器响应等内容。

HttpWebRequest request = null;
WebResponse response = null;

try
{

                string myURL = "https://blah.blah.gov/themagicform.cfm"; //The URL for my requests:
                request = (HttpWebRequest)WebRequest.Create(myURL); // Create a request using a URL that can receive a post.
                request.Credentials = new NetworkCredential("MyUserName", "MyPassWord"); //The credentials for the website.
                request.Method = "POST"; // Set the Method property of the request to POST.
                //request.ContentType = "text/xml";   // Set the ContentType property of the WebRequest.
                request.ContentType = "application/x-www-form-urlencoded";
                // Specify Headers
                request.Headers.Add("HTTP_HOST", "MyZone");
                request.Headers.Add("HTTP_USER_AGENT", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.1.4322)");
                request.Headers.Add("HTTP_ACCEPT", "text/xml");

                StreamWriter writer = new StreamWriter(request.GetRequestStream()); // Wrap the request stream with a text-based writer

                writer.WriteLine(XMLDoc); // Write the xml text into the stream
                writer.Close();

    /* Previously I tried:
                string postData = XMLDoc;   // Create POST data and convert it to a byte array.
                byte[] byteArray = Encoding.UTF8.GetBytes(postData);
                request.ContentLength = byteArray.Length;   // Set the ContentLength property of the WebRequest.
                Stream dataStream = request.GetRequestStream(); // Get the request stream.
                dataStream.Write(byteArray, 0, byteArray.Length); // Write the data to the request stream.
                dataStream.Close(); // Close the Stream object - which submits the "form" data.
                */

Stream dataStream = null;

                // Send the data to the webserver
                response = request.GetResponse(); // Get the response.
                lbl_ResponseInfo.Text = ((HttpWebResponse)response).StatusDescription.ToString(); // Display the status.

                dataStream = response.GetResponseStream(); // Get the stream containing content returned by the server.
                StreamReader incomingStreamReader = new StreamReader(dataStream); // Open the stream using a StreamReader for easy access.
                string responseFromServer = incomingStreamReader.ReadToEnd();// Read the content.
                // Display the content. XMLResponse is a special type of label on my asp page
                XMLResponse.Visible = true;
                XMLResponse.TransformSource = "defaultss.xslt";
                XMLResponse.DocumentContent = responseFromServer;
                lbl_Received.Visible = true;

                // Clean up the streams.
                incomingStreamReader.Close();
                dataStream.Close();
                response.Close();

                //Display the XML we sent
                XMLSent.Visible = true;
                XMLSent.TransformSource = "defaultss.xslt";
                XMLSent.DocumentContent = XMLDoc;
                lbl_Sent.Visible = true;
            }

            catch (WebException webEx)
            {
                lbl_ResponseInfo.Text = webEx.Message.ToString();
            }
            catch (Exception ex)
            {
                lbl_ResponseInfo.Text = ex.Message.ToString();
            }
            finally
            {
                if (request != null) request.GetRequestStream().Close();
                if (response != null) response.GetResponseStream().Close();

}