24.有效的数独(medium)

1.题目链接:

36. 有效的数独 - 力扣(LeetCode)36. 有效的数独 - 请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。 1. 数字 1-9 在每一行只能出现一次。 2. 数字 1-9 在每一列只能出现一次。 3. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图) 注意: * 一个有效的数独(部分已被填充)不一定是可解的。 * 只需要根据以上规则,验证已经填入的数字是否有效即可。 * 空白格用 '.' 表示。 示例 1:[https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2021/04/12/250px-sudoku-by-l2g-20050714svg.png]输入:board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]输出:true示例 2:输入:board = [["8","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]输出:false解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。 提示: * board.length == 9 * board[i].length == 9 * board[i][j] 是一位数字(1-9)或者 '.'https://leetcode.cn/problems/valid-sudoku/description/2.题目描述:

请你判断一个 9 x 9 的数独是否有效。只需要根据以下规则 ,验证已经填入的数字是否有效即可。​

数字 1-9 在每一行只能出现一次。​

数字 1-9 在每一列只能出现一次。​

数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)​ ​
注意:
一个有效的数独(部分已被填充)不一定是可解的。

只需要根据以上规则,验证已经填入的数字是否有效即可。

空白格用 '.' 表示。​

示例 1:​

输入:
board = ​
[["5","3",".",".","7",".",".",".","."]​
,["6",".",".","1","9","5",".",".","."]​
,[".","9","8",".",".",".",".","6","."]​
,["8",".",".",".","6",".",".",".","3"]​
,["4",".",".","8",".","3",".",".","1"]​
,["7",".",".",".","2",".",".",".","6"]​
,[".","6",".",".",".",".","2","8","."]​
,[".",".",".","4","1","9",".",".","5"]​
,[".",".",".",".","8",".",".","7","9"]]​
输出:true​

示例 2:​

输入:
board = ​
[["8","3",".",".","7",".",".",".","."]​
,["6",".",".","1","9","5",".",".","."]​
,[".","9","8",".",".",".",".","6","."]​
,["8",".",".",".","6",".",".",".","3"]​
,["4",".",".","8",".","3",".",".","1"]​
,["7",".",".",".","2",".",".",".","6"]​
,[".","6",".",".",".",".","2","8","."]​
,[".",".",".","4","1","9",".",".","5"]​
,[".",".",".",".","8",".",".","7","9"]]​
输出:false​
解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。​

                   提示:
                            board.length == 9​
                            board[i].length == 9​
                            board[i][j] 是一位数字(1-9)或者 '.'​
3. 解法:
算法思路:
创建三个数组标记行、列以及3*3 小方格中是否出现 1~9  之间的数字即可。​

Java算法代码:

class Solution {
    boolean [][] row,col;
    boolean [][][] grid;
    public boolean isValidSudoku(char[][] board) {
        row = new boolean[9][10];
        col = new boolean[9][10];
        grid = new boolean[3][3][10];

        for(int i = 0; i<9;i++){
            for(int j = 0; j<9;j++){
                if(board[i][j] != '.'){
                    int num = board[i][j] - '0';
                    //是否有效
                    if(row[i][num] || col[j][num] || grid[i/3][j/3][num])
                        return false;
                    row[i][num] = col[j][num] = grid[i/3][j/3][num] = true;
                }
            }
        }
        return true;
    }
}

运行结果:

递归展开:

逻辑展开:

这个题还是要注意体题干,是要求干什么。不要理解错了。

并不需要填写数独。

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记住,相信你的递归函数,它可以做到!

记住,不理解时候,去尝试手动展开!

记住,逻辑展开(你不可能对所有的题目都进行手动展开)!

      要**随机生成一个有效数独谜题**,必须满足以下条件: - 数独有**唯一解** - 谜题具有一定的**难度等级**(如简单、中等、困难) - 初始数字尽可能对称分布(美观) - 不能出现矛盾或无解的情况 --- ### ✅ 解决方案:先生成完整有效终盘 → 逐步挖空 → 验证唯一解 我们采用经典的三步法: 1. **使用回溯算法生成一个完整的合法数独终盘(全填满)** 2. **从终盘中随机挖去一些格子(按难度控制数量)** 3. **每次挖空后,用求解器验证是否仍然只有唯一解** --- ## 🧩 完整 JavaScript 实现(接上一个项目) 以下是可以在你原有数独游戏中添加的“**随机生成新谜题**”功能代码。 ```javascript // 在原有 JS 中加入以下函数 /** * 生成一个完整的、随机的数独终盘 */ function generateFullGrid() { const grid = Array(9).fill().map(() => Array(9).fill(0)); // 随机化填充顺序以增加多样性 function shuffle(array) { for (let i = array.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [array[i], array[j]] = [array[j], array[i]]; } return array; } function fill(grid) { for (let r = 0; r < 9; r++) { for (let c = 0; c < 9; c++) { if (grid[r][c] === 0) { const nums = shuffle([1, 2, 3, 4, 5, 6, 7, 8, 9]); for (let num of nums) { if (isValid(grid, r, c, num)) { grid[r][c] = num; if (fill(grid)) return true; grid[r][c] = 0; } } return false; } } } return true; } fill(grid); return grid; } /** * 挖洞并确保唯一解 * @param {number[][]} solution - 完整终盘 * @param {number} holes - 要挖去的格子数(难度控制) * @returns {number[][]} 可玩谜题 */ function createPuzzleWithHoles(solution, holes = 40) { const puzzle = JSON.parse(JSON.stringify(solution)); // 复制终盘 const positions = []; // 生成所有位置 [(0,0), (0,1), ..., (8,8)] for (let r = 0; r < 9; r++) { for (let c = 0; c < 9; c++) { positions.push([r, c]); } } // 随机打乱位置 shuffle(positions); let removed = 0; for (let [r, c] of positions) { if (removed >= holes) break; const temp = puzzle[r][c]; puzzle[r][c] = 0; // 检查是否仍只有唯一解 if (countSolutions(puzzle) === 1) { removed++; } else { puzzle[r][c] = temp; // 恢复,否则不唯一 } } return puzzle; } /** * 计算某个谜题的解的数量(最多数两个,用于判断唯一性) */ function countSolutions(grid) { let count = 0; function search(g) { if (count > 1) return; // 提前退出 for (let r = 0; r < 9; r++) { for (let c = 0; c < 9; c++) { if (g[r][c] === 0) { for (let num = 1; num <= 9; num++) { if (isValid(g, r, c, num)) { g[r][c] = num; search(g); g[r][c] = 0; if (count > 1) return; } } return; } } } // 到达这里说明找到了一个完整解 count++; } const copy = JSON.parse(JSON.stringify(grid)); search(copy); return count; } /** * 打乱数组(辅助函数) */ function shuffle(array) { for (let i = array.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [array[i], array[j]] = [array[j], array[i]]; } return array; } ``` --- ## 🔘 添加“新游戏”按钮来使用它 在 HTML 的按钮区域增加一个按钮: ```html <button id="newGameBtn">新游戏</button> ``` 然后在 JS 中添加事件监听: ```javascript const newGameBtn = document.getElementById("newGameBtn"); newGameBtn.addEventListener("click", () => { // 选择难度:挖空数量(越多越难) const difficulty = { easy: 40, medium: 50, hard: 60 }; const holes = difficulty.medium; // 可改为用户选择 const fullGrid = generateFullGrid(); // 步骤1:生成终盘 const newPuzzle = createPuzzleWithHoles(fullGrid, holes); // 步骤2:挖洞+验证 // 更新全局变量 puzzle = newPuzzle; board = JSON.parse(JSON.stringify(puzzle)); solution = fullGrid; selectedCell = null; renderBoard(); alert("已生成新游戏!"); }); ``` --- ## 🎯 难度说明(挖空数量参考) | 难度 | 挖空数量 | 剩余提示数 | |------|----------|-----------| | 简单 | 30~40 | 41~51 | | 中等 | 41~55 | 26~40 | | 困难 | 56~64 | 17~25 | > ⚠️ 注意:超过约 64 个空可能导致无唯一解或生成时间变长。 --- ## ⏱️ 性能优化建议 虽然上述方法准确,但 `countSolutions` 是指数级复杂度。为提升性能可做如下改进: 1. **限制搜索深度**:只允许找到两个解就停止。 2. **启发式挖空**:优先挖对称位置(如中心对称),提高美观性。 3. **缓存常见模式**:预生成一批谜题,随机选取,避免实时计算。 4. **Web Worker 异步处理**:防止界面卡顿。 --- ## ✅ 示例:如何集成进你的原项目? 只需将上面的函数插入你原来的 `<script>` 标签中,并添加按钮即可: ```html <!-- 放在 controls div 内 --> <button id="newGameBtn">新游戏</button> ``` --- ## ✅ 输出效果 调用后会: - 生成一个全新的、有唯一解的数独谜题 - 用户可以继续进行“求解”、“答案”、“重置”等操作 - 所有原有功能依然可用 ---
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