Given an unsorted integer array, find the first missing positive integer.
For example,
Given [1,2,0]
return 3
,
and [3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
算法:将nums[i] 放置到正确的位置
class Solution {
public:
int firstMissingPositive(vector<int>& nums) {
int n = nums.size();
for(int i = 0; i < n; i++)
while(nums[i] > 0 && nums[i] <= n && nums[nums[i] - 1] != nums[i])
swap(nums[nums[i] - 1] , nums[i]);
for(int i = 0; i < n; i++)
if(nums[i] != i + 1) return i + 1;
return n + 1;
}
};