水题——415A. Mashmokh and Lights

最新推荐文章于 2017-10-19 20:45:56 发布

转载最新推荐文章于 2017-10-19 20:45:56 发布 · 154 阅读

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原文链接：http://www.cnblogs.com/yepiaoling/p/5313245.html

本文解析了一个有趣的问题，即如何确定每个工厂灯光是由哪个按钮关闭的。通过一系列操作，文章详细阐述了如何使用C++实现这一策略，确保所有灯光在经过特定按钮操作后都能正确关闭。

Mashmokh works in a factory. At the end of each day he must turn off all of the lights.

The lights on the factory are indexed from 1 to n. There are n buttons in Mashmokh's room indexed from 1 to n as well. If Mashmokh pushes button with index i, then each light with index not less than i that is still turned on turns off.

Mashmokh is not very clever. So instead of pushing the first button he pushes some of the buttons randomly each night. He pushed m distinct buttonsb1, b2, ..., bm (the buttons were pushed consecutively in the given order) this night. Now he wants to know for each light the index of the button that turned this light off. Please note that the index of button bi is actually bi, not i.

Please, help Mashmokh, print these indices.

Input

The first line of the input contains two space-separated integers n and m (1 ≤ n, m ≤ 100), the number of the factory lights and the pushed buttons respectively. The next line contains m distinct space-separated integers b1, b2, ..., bm (1 ≤ bi ≤ n).

It is guaranteed that all lights will be turned off after pushing all buttons.

Output

Output n space-separated integers where the i-th number is index of the button that turns the i-th light off.

Examples

input

5 4
4 3 1 2

output

1 1 3 4 4

input

5 5
5 4 3 2 1

output

1 2 3 4 5

Note

In the first sample, after pressing button number 4, lights 4 and 5 are turned off and lights 1, 2 and 3 are still on. Then after pressing button number 3, light number 3 is turned off as well. Pressing button number 1 turns off lights number 1 and 2 as well so pressing button number 2 in the end has no effect. Thus button number 4 turned lights 4 and 5 off, button number 3 turned light 3 off and button number 1 turned light 1 and 2 off.

题意：有n盏灯和开关1,，2，3...第n个开关可以把第n个灯及其后面的灯关闭，操作了m次，每次按下一个开关，保证所有的灯最后都被关闭了，要求输出每个灯是被哪个开关关闭的。

 1 /*A*/
 2 #include<cstdio>
 3 #include<cstring>
 4 using namespace std;
 5 
 6 int main()
 7 {
 8     int n,m;
 9     int a[100+10];
10     int ans[100+10];
11     int vis[100+10];
12     while(scanf("%d%d",&n,&m)!=EOF)
13     {
14         for(int i=0;i<m;i++)
15             scanf("%d",&a[i]);
16         memset(ans,0,sizeof(ans));
17         memset(vis,0,sizeof(vis));
18         for(int i=0;i<m;i++)
19         {
20             if(vis[a[i]]==0)
21             {
22                 for(int j=a[i];j<=n;j++)
23                 {
24                     if(vis[ans[j]]==0)
25                     {
26                         ans[j]=a[i];
27                         vis[j]=1;
28                     }
29                 }
30             }
31         }
32         printf("%d ",ans[1]);
33         for(int i=2;i<=n;i++)
34             printf("%d ",ans[i]);
35         printf("\n");
36     }
37     return 0;
38 }

转载于:https://www.cnblogs.com/yepiaoling/p/5313245.html