长按键的判断

最新推荐文章于 2024-08-23 01:52:28 发布

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#手机

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TKeyResponse OfferKeyEventL(const TKeyEvent& aKeyEvent, TEventCode aType)
{
……
//打印日志aType iRepeats:

switch (aKeyEvent.iCode)
{
  case EKeyUpArrow:
  {
   //按键处理
   break;
  }
  case EKeyDownArrow:
  {
   //按键处理
   break;
  }
}
……
}

短按键日志信息：
EEventKeyDown iRepeats:0
EEventKey iRepeats:0
EEventKeyUp iRepeats:0

长按键日志信息：
EEventKeyDown iRepeats:0
EEventKey      iRepeats:0          //第一次会走短按键处理
EEventKey      iRepeats:1
EEventKey      iRepeats:1
……
EEventKey      iRepeats:1
EEventKeyUp    iRepeats:0

方案:上下键延迟到弹起时处理。

TKeyResponse OfferKeyEventL(const TKeyEvent& aKeyEvent, TEventCode aType)
{
   ……
    if (EEventKeyUp == aType && iKeyEvent.iRepeats == 0)
    {
        if (iKeyEvent.iCode == EKeyUpArrow)
        {
            HandleUpArrowEventL(iKeyEvent, EEventKey);
        }

        if (iKeyEvent.iCode == EKeyDownArrow)
        {
            HandleDownArrowEventL(iKeyEvent, EEventKey);
        }
    }

//增加成员变量iKeyEvent,保存上一次aKeyEvent。
iKeyEvent = aKeyEvent;

  switch (aKeyEvent.iCode)
  {
      case EKeyUpArrow:
        {
     if (aKeyEvent.iRepeats == 1)
     {
      //长按键处理
     }
     break;
       }
       case EKeyDownArrow:
       {
     if (aKeyEvent.iRepeats == 1)
     {
      //长按键处理
     }
     break;
    }
    //其它键处理不变
}
……
}

但是有些手机iRepeats不同

E52手机长按键日志信息：
EEventKeyDown   iRepeats:0
EEventKey       iRepeats:0
EEventKey       iRepeats:0
EEventKey       iRepeats:536975507
EEventKey       iRepeats:536975507
……
EEventKey       iRepeats:536975507
EEventKeyUp     iRepeats:536975507

6700s手机iRepeats始终为0

解决方法：

TKeyResponse OfferKeyEventL(const TKeyEvent& aKeyEvent, TEventCode aType)
{
   ……

  if ((EEventKeyUp == aType) || (EEventKeyDown == aType))
    {
        iKeyEventNum = 0;
    }
    else
    {
        iKeyEventNum++;
    }

TKeyEvent keyEvent = aKeyEvent;

    if (3 <= iKeyEventNum)
    {
        keyEvent.iRepeats = 1;
        iKeyEventNum = 3;
    }

    if (EEventKeyUp == aType && iKeyEvent.iRepeats == 0)
    {
        if (iKeyEvent.iCode == EKeyUpArrow)
        {
            HandleUpArrowEventL(iKeyEvent, EEventKey);
        }

        if (iKeyEvent.iCode == EKeyDownArrow)
        {
            HandleDownArrowEventL(iKeyEvent, EEventKey);
        }
    }

//增加成员变量iKeyEvent
iKeyEvent = keyEvent;

  switch (keyEvent.iCode)
  {
      case EKeyUpArrow:
        {
     if (keyEvent.iRepeats == 1)
     {
      //长按键处理
     }
     break;
       }
       case EKeyDownArrow:
       {
     if (keyEvent.iRepeats == 1)
     {
      //长按键处理
     }
     break;
    }
    //其它键处理不变
}
……
}