函数中结构体的传递

 

#include <stdio.h>

typedef struct Mystruct
{
 int iTest;
}Mystruct,*LPMystruct;

void Test(LPMystruct s )
{
 s->iTest = 8; 
}

void Test2(Mystruct s )
{
 s.iTest = 7; 
}

int main(int argc, char *argv[])
{
  
 Mystruct s1;
 s1.iTest = 3;
 printf("%d\n",s1.iTest);
 Test(&s1);
 printf("%d\n",s1.iTest);
 Test2(s1);                  //改变不了s.Itest 的值，还是8
 printf("%d\n",s1.iTest);
 
 return 0;
}