22. Generate Parentheses

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
[
  "((()))",
  "(()())",
  "(())()",
  "()(())",
  "()()()"


做出来了 效率还行 
n parenthesis => n left + n right => 2*n positions.Each time, one left or right should be chosen.
We can always pick left.
If there are more right remained, we can put right.

public ArrayList<String> generateParenthesis(int n) { 
    ArrayList<String> results = new ArrayList<>(); 
    generateParenthesis(results, "", n, n);
    return results;
}
public void generateParenthesis(ArrayList<String> results, String prefix, int left, int right) {
    if (left == 0 && right == 0) { 
        results.add(prefix); 
        return;
    }
    if (left > 0) {
        generateParenthesis(results, prefix+"(", left-1, right); 
    }
    if (left < right) {
        generateParenthesis(results, prefix+")", left, right-1);
    } 
}



#include <cassert> /// for assert #include <iostream> /// for I/O operation #include <vector> /// for vector container /** @brief Backtracking algorithms @namespace backtracking / namespace backtracking { /* @brief generate_parentheses class */ class generate_parentheses { private: std::vectorstd::string res; ///< Contains all possible valid patterns void makeStrings(std::string str, int n, int closed, int open); public: std::vectorstd::string generate(int n); }; /** @brief function that adds parenthesis to the string. @param str string build during backtracking @param n number of pairs of parentheses @param closed number of closed parentheses @param open number of open parentheses */ void generate_parentheses::makeStrings(std::string str, int n, int closed, int open) { if (closed > open) // We can never have more closed than open return; if ((str.length() == 2 * n) && (closed != open)) { // closed and open must be the same return; } if (str.length() == 2 * n) { res.push_back(str); return; } makeStrings(str + ')', n, closed + 1, open); makeStrings(str + '(', n, closed, open + 1); } /** @brief wrapper interface @param n number of pairs of parentheses @return all well-formed pattern of parentheses */ std::vectorstd::string generate_parentheses::generate(int n) { backtracking::generate_parentheses::res.clear(); std::string str = “(”; generate_parentheses::makeStrings(str, n, 0, 1); return res; } } // namespace backtracking /** @brief Self-test implementations @returns void */ static void test() { int n = 0; std::vectorstd::string patterns; backtracking::generate_parentheses p; n = 1; patterns = {{“()”}}; assert(p.generate(n) == patterns); n = 3; patterns = {{“()()()”}, {“()(())”}, {“(())()”}, {“(()())”}, {“((()))”}}; assert(p.generate(n) == patterns); n = 4; patterns = {{“()()()()”}, {“()()(())”}, {“()(())()”}, {“()(()())”}, {“()((()))”}, {“(())()()”}, {“(())(())”}, {“(()())()”}, {“(()()())”}, {“(()(()))”}, {“((()))()”}, {“((())())”}, {“((()()))”}, {“(((())))”}}; assert(p.generate(n) == patterns); std::cout << “All tests passed\n”; } /** @brief Main function @returns 0 on exit */ int main() { test(); // run self-test implementations return 0; } 在这段代码的基础上为C++初学者出几个练习题?
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03-08
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