*Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Output
One integer per line representing the maximum of the total value (this number will be less than 231).
Sample Input
1 5 10 1 2 3 4 5 5 4 3 2 1
Sample Output
140-1背包一.滚动一维数组二.二维数组#include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <cctype> #include <iostream> #include <algorithm> #include <vector> #include <stack> #include <deque> #include <queue> #include <set> #include <list> #include <map> #include <string> using namespace std; #define infinity 2147483647 int dp[10005],v[10005],w[10005]; int maxx(int a,int b) { if(a>b) return a; else return b; } int main() { int n,i,j,m,t; while(scanf("%d",&t)!=EOF) { while(t--) { scanf("%d %d",&n,&m); for(i=1;i<=n;i++) scanf("%d",&w[i]); for(i=1;i<=n;i++) scanf("%d",&v[i]); memset(dp,0,sizeof(dp)); for(i=1;i<=n;i++) { for(j=m;j>=v[i];j--) //必须反举 { dp[j]=maxx(dp[j],dp[j-v[i]]+w[i]); } } printf("%d\n",dp[m]); } } return 0; }
#include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <cctype> #include <iostream> #include <algorithm> #include <vector> #include <stack> #include <deque> #include <queue> #include <set> #include <list> #include <map> #include <string> using namespace std; #define infinity 2147483647 int maxx(int a,int b) { if(a>b) return a; else return b; } int f[10005][10005],v[10005],w[10005]; int main() { int n,i,j,m,t; while(scanf("%d",&t)!=EOF) { while(t--) { scanf("%d %d",&n,&m); for(i=1;i<=n;i++) scanf("%d",&w[i]); for(i=1;i<=n;i++) scanf("%d",&v[i]); for(j=0;j<=m;j++) { f[0][j]=0; } for(i=1;i<=n;i++) { for(j=0;j<=m;j++) { f[i][j]=f[i-1][j]; if(v[i]<=j) { f[i][j]=maxx(f[i][j],f[i-1][j-v[i]]+w[i]); } } } printf("%d\n",f[n][m]); } } return 0; }