Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.
Your algorithm should run in O(n) complexity.
import java.util.ArrayList;
import java.util.Arrays;
public class Solution {
public int longestConsecutive(int[] num) {
Arrays.sort(num);
ArrayList<Integer> temp = new ArrayList<Integer>();
for(int i = 0;i<num.length;i++){
if(!temp.contains(num[i])){
temp.add(num[i]);
}
}
int max = 1;
int count = 1;
for(int i = 0;i<temp.size();i++){
if(i!=temp.size()-1&& temp.get(i+1)-temp.get(i) ==1){
count = count +1 ;
}
else{
count = 1;
}
if(count>=max){
max = count;
}
}
return max;
}
}
本文介绍了一种寻找整数数组中最长连续元素序列的算法,并提供了一个Java实现示例。该算法首先对数组进行排序,然后去除重复元素,最后通过遍历数组来计算最长连续序列的长度。
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