PTA1001 A+B Format

最新推荐文章于 2020-12-24 18:40:26 发布

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最新推荐文章于 2020-12-24 18:40:26 发布

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本文链接：https://blog.youkuaiyun.com/csdn_muxin/article/details/81033874

本文介绍了一个简单的编程问题——1001A+B，该问题要求计算两个整数之和，并以标准格式输出结果。标准格式是指用逗号分隔每三位数字（除非总位数少于四位）。文章提供了完整的C++代码实现，涵盖了输入处理、计算和格式化输出等关键步骤。

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1001 A+B Format (20)（20 分）

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

代码：

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<cmath>
#include<cstdlib>
using namespace std;

int main()
{
    int a,b;
    int i,num,t;
    char s[20];
    cin>>a>>b;
    a+=b;
    b=a;
    a=abs(a);
    num=0;
    t=0;
    while(a)
    {
        s[num++]=a%10+'0';
        t++;
        a=a/10;
        if(t==3&&a!=0)//注意刚好是三个数的情况
        {
            t=0;
            s[num++]=',';
        }
    }
    if(b<0)
        s[num++]='-';
    if(b==0) cout<<"0";//注意结果为零的情况
    for(i=num-1;i>=0;i--)
    {
        cout<<s[i];
    }
return 0;
}