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A robot is located at the top-left corner of a m x n grid (marked ‘Start’ in the diagram below).The robot can only move either down or right at any point in time. The robot is trying to reach the botto

算法1：二重循环，复杂度O(n²)import java.util.Scanner;public class MaxSubSum1 { public static int maxSubSum(int[] array) { int thisSum, maxSum = 0; for (int i = 0; i < array.length; i ++) {

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.Note: You can only move either down or right at any

斐波那契数列题目描述 大家都知道斐波那契数列：f(0) = 0, f(1) = 1, f(n) = f(n - 1) + f(n - 2) 现在要求输入一个整数n，请你输出斐波那契数列的第n项。 n&amp;lt;=39思路：如果直接用f(n) = f(n - 1) + f(n - 2)递归，重复计算次数太多，效率低下；用自下而上的循环较好，通过f(0)和f(1)算出f(2)，再根据已知的f...

题目描述： 给你一根长度为n的绳子，请把绳子剪成m段（m和n都是整数，n &amp;gt; 1，m &amp;gt; 1），每段绳子的长度记为k[0],k[1],k[2]…k[m]。请问k[0] * k[1] * … * k[m]可能的最大乘积是多少？例如，当绳子的长度为8时，我们把它分别剪成2,3,3的三段，此时乘积最大是18。思路一：利用动态规划，自下而上的循环，原理同斐波那契数列，时间复杂度O(n²)...