题目:
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1
and 0
respectively
in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is 2
.
Note: m and n will be at most 100.
class Solution {
public:
int uniquePathsWithObstacles(vector<vector<int> > &obstacleGrid) {
int m = obstacleGrid.size();
int n = obstacleGrid[0].size();
f[0][0] = obstacleGrid[0][0] == 0 ? 1 : 0;
for (int i = 1; i < m; i++)
f[i][0] = obstacleGrid[i][0] == 0 ? f[i-1][0] : 0;
for (int j = 1; j < n; j++)
f[0][j] = obstacleGrid[0][j] == 0 ? f[0][j-1] : 0;
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
f[i][j] = obstacleGrid[i][j] == 0 ? f[i - 1][j] + f[i][j - 1] : 0;
}
}
return f[m - 1][n - 1];
}
private:
int f[100][100];
};