Problem 6 自然数求差

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Answer:

25164150

public class Squares { public static void main(String args[]){ int sum=0; int mul=1; int mulsum=0; for(int i=1;i<=100;i++){ sum+=i; mul=i*i; mulsum+=mul; } System.out.println(sum*sum-mulsum); } }