hdu1087 Super Jumping! Jumping! Jumping!

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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1087

经典dp的一个小变形,用dp[i]表示第i个位置上的max,则dp[i]=a[i]+dp]j],(a[j]<a[i]&&max(dp[j])),然后输出max(dp)即可;

//代码中含全角空格

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
const int N=1010;
int n,a[N];
long long dp[N],maxn;

int main()
{
    while(cin>>n&&n){
        for(int i=0;i<n;i++)
            cin>>a[i];
        maxn=-1;
        memset(dp,0,sizeof(dp));
        for(int i=0;i<n;i++){
            long long tmp=0;
        for(int j=i-1;j>=0;j--)
            if(a[j]<a[i])tmp=max(dp[j],tmp);//找max(dp[j])  <span style="font-family: Arial; font-size: 14px; line-height: 26px;">a[j]<a[i]&&max(dp[j])</span>
        dp[i]+=(tmp+a[i]);
        maxn=max(dp[i],maxn);           
        }
        printf("%I64d\n",maxn);
    }
    return 0;
}

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