A1082 Read Number in Chinese (25) 字符串处理

本题是字符串转换问题，在设计计算的时候很明显是以四个数字为一节进行计算，所以可以每次分成四个数字一组进行判断，用left和right来表示边界，设计千百十计算，最后利用len和right来设计万和亿的计算就好了。

#include<cstdio>
#include<cstring>
char num[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
char wei[5][5]={"Shi","Bai","Qian","Wan","Yi"};
int main()
{
	char str[15];
	scanf("%s",str);
	int len=strlen(str);
	int left=0,right=len-1;
	if(str[0]=='-')
	{
		printf("Fu");
		left++;
	}
	while(left+4<=right)
	{
		right-=4;
	}
	while(left<len)
	{
		bool flag=false;
		bool isprint=false;
		while(left<=right)
		{
			if(left>0&&str[left]=='0')
			{
				flag=true;
			}
			else
			{
				if(flag==true)
				{
					printf(" ling");
					flag=false;
				}
				if(left>0)
				printf(" ");
				printf("%s",num[str[left]-'0']);
				isprint=true;
				if(left!=right)
				{
					printf(" %s",wei[right-left-1]);
				}
			}
			left++;
		}
		if(isprint==true&&right!=len-1)
		{
			printf(" %s",wei[(len-right-1)/4+2]);
			right+=4;
		}	
	}
}