UVA 621 - Secret Research（数学）

最新推荐文章于 2019-09-27 00:34:31 发布

coco430

最新推荐文章于 2019-09-27 00:34:31 发布

阅读量613

点赞数

分类专栏：数学题 UVA

本文链接：https://blog.youkuaiyun.com/coco430/article/details/9469229

版权

UVA 同时被 2 个专栏收录

41 篇文章

订阅专栏

数学题

14 篇文章

订阅专栏

Secret Research

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result', `negative result', `experiment failed' or `experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:



positive result 		 S = 1 or S = 4 or S = 78 

negative result 		 S = S35 

experiment failed 		 S = 9S4 

experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output

For each analysed sequence of digits the following lines should be sent to output (in separate lines):


		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input

Sample Output

+
-
?
*

Miguel A. Revilla
2000-01-10

================================

直接按照题意寻找字符即可

#include <iostream>
#include <cstdio>
#include <cstring>

using namespace std;

char str[1111];

int main()
{
    int t;
    scanf("%d",&t);
    getchar();
    while(t--)
    {
        gets(str);
        int len=strlen(str);
        if((len==1&&(str[0]=='1'||str[0]=='4'))||(len==2&&str[0]=='7'&&str[1]=='8'))
            cout<<"+"<<endl;
        else if(str[len-2]=='3'&&str[len-1]=='5')
            cout<<"-"<<endl;
        else if(str[0]=='9'&&str[len-1]=='4')
            cout<<"*"<<endl;
        else cout<<"?"<<endl;

    }
    return 0;
}