817. Linked List Components

标定匹配list和对应的链表，首先可以把链表转化为线性表，考虑到Python的dict自带排序效果，引入有序字典OrderedDict，标记字典中已经在G中出现过的为1，未出现过的标记为0.

from collections import OrderedDict
class Solution:
    def numComponents(self, head, G):
        """
        :type head: ListNode
        :type G: List[int]
        :rtype: int
        """
        dict1 = OrderedDict()
        while head is not None:
            dict1[head.val] = 0
            head = head.next
        for index in G:
            dict1[index] = 1
        isbreak = True          #标记前一个是否是断开项
        count = 0
        for part in dict1.values():
            if isbreak:
                if part == 1:
                    count += 1
                    isbreak = False
            else:
                if part == 0:
                    isbreak = True
        return count
#end def