计算数字列表元素差值的绝对值最小的数

求最优的算法

vli = [9,1,7,2,3,4,1]

svli = sorted(vli)

deffer = []
result = []

for i in range(len(svli)):
	if i<len(svli)-1:
		if len(deffer) ==0:
			deffer.append(svli[i+1]-svli[i])
			result.append([svli[i+1],svli[i]])
		else:
			if deffer[0] > abs(svli[i+1]-svli[i]):
				deffer = []
				deffer.append(svli[i+1]-svli[i])
				result.append([svli[i+1],svli[i]])
			elif deffer[0] == abs(svli[i+1]-svli[i]):
				deffer.append(svli[i+1]-svli[i])
				result.append([svli[i+1],svli[i]])
print(deffer)
print(result)

• 运行结果b