HDU-6045-Is Derek lying?

Is Derek lying?

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1598    Accepted Submission(s): 826

Problem Description

Derek and Alfia are good friends.Derek is Chinese,and Alfia is Austrian.This summer holiday,they both participate in the summer camp of Borussia Dortmund.During the summer camp,there will be fan tests at intervals.The test consists of N choice questions and each question is followed by three choices marked “A” “B” and “C”.Each question has only one correct answer and each question is worth 1 point.It means that if your answer for this question is right,you can get 1point.The total score of a person is the sum of marks for all questions.When the test is over,the computer will tell Derek the total score of him and Alfia.Then Alfia will ask Derek the total score of her and he will tell her: “My total score is X,your total score is Y.”But Derek is naughty,sometimes he may lie to her. Here give you the answer that Derek and Alfia made,you should judge whether Derek is lying.If there exists a set of standard answer satisfy the total score that Dereksaid,you can consider he is not lying,otherwise he is lying.

 

Input

The first line consists of an integer T,represents the number of test cases.

For each test case,there will be three lines.

The first line consists of three integers N,X,Y,the meaning is mentioned above.

The second line consists of N characters,each character is “A” “B” or “C”,which represents the answer of Derek for each question.

The third line consists of N characters,the same form as the second line,which represents the answer of Alfia for each question.

Data Range:1≤N≤80000,0≤X,Y≤N,∑Ti=1N≤300000

 

Output

For each test case,the output will be only a line.

Please print “Lying” if you can make sure that Derek is lying,otherwise please print “Not lying”.

 

Sample Input

2
3 1 3
AAA
ABC
5 5 0
ABCBC
ACBCB

 

Sample Output

Not lying
Lying

  

解题代码

 

#include <iostream>
#include <stdio.h>
#include <math.h>
using namespace std;
char ch[80005];
char sh[80005];
int main()
{
    int T;
    scanf("%d",&T);
    while(T--)
    {
        int N,X,Y;
        scanf("%d%d%d",&N,&X,&Y);
        getchar();
        scanf("%s",ch);
        getchar();
        scanf("%s",sh);
        int count1=0;
        int sum=X+Y;//计算两个人最大可能得到的分数总和最低应该是X+Y
        int mul=fabs(X-Y);//两个人不同的答案最低应该有X-Y个
        for(int i=0;i<N;i++)
        {
            if(ch[i]!=sh[i])
                count1++;
            if(count1==mul)
                break;
        }

        if(count1<mul)
        {
            printf("Lying\n");
            continue;
        }
        count1=0;
        for(int i=0;i<N;i++)
        {
            if(ch[i]==sh[i])//当两个人答案相同时都加分，当答案不同的时候随便一个加一分，
                count1+=2;//这样得到的才是两个得到的分数的总和的最大可能值

            else
                count1+=1;
            if(count1==sum)
                break;
        }
        if(count1<sum)
            printf("Lying\n");
        else
            printf("Not lying\n");
    }
    return 0;
}