*寒假水20——Snooker

 

background: 
 Philip likes to play the QQ game of Snooker when he wants a relax, though he was just a little vegetable-bird. Maybe you hadn't played that game yet, no matter, I'll introduce the rule for you first. 
 There are 21 object balls on board, including 15 red balls and 6 color balls: yellow, green, brown, blue, pink, black. 
 The player should use a white main ball to make the object balls roll into the hole, the sum of the ball's fixed value he made in the hole is the player's score. The player should firstly made a red ball into the hole, after that he gains red-ball's value(1 points), then he gets the chance to make a color ball, then alternately. The color ball should be took out until all the red-ball are in the hole. In other word, if there are only color balls left on board, the player should hit the object balls in this order: yellow(2 point), green(3 point), brown(4 point), blue(5 point), pink(6 point), black(7 point), after the ball being hit into the hole, they are not get out of the hole, after no ball left on board, the game ends, the player who has 
the higher score wins the game. PS: red object balls never get out of the hole. 
 I just illustrate the rules that maybe used, if you want to contact more details, visit http://sports.tom.com/snooker/ after 
the contest. 

for example, if there are 12 red balls on board(if there are still red ball left on board, it can be sure that all the color 
balls must be on board either). So suppose Philp can continuesly hit the ball into the hole, he can get the maximun score is 
12 * 1 (12 red-ball in one shoot) + 7 * 12(after hit a red ball, a black ball which was the most valuable ball should be the target) + 2 + 3 + 4 + 5 + 6 + 7(when no red ball left, make all the color ball in hole). 
 Now, your task is to judge whether Philip should make the decision to give up when telling you the condition on board(How many object balls still left not in the hole and the other player's score). If Philp still gets the chance to win, just print "Yes", otherwise print "No". (PS: if the max score he could get on board add his current score is equal to the opponent's current score, still output "Yes") 

InputThe first line contains a numble N indicating the total conditions. Then followed by N lines, each line is made of three integers: 
Ball_Left P_Score O_Score represeting the ball number left on board, Philp's current score, and the opponent's current score. 
All the input value are in 32 bit integer value range.OutputYou should caculate the max score left Philp can gain, and judge whether he has the possiblity to win.Sample Input

2
12 1 1
1 30 39

Sample Output

Yes
No

#include<iostream>
using namespace std;
int main()
{
	int n,i,ball,sc1,sc2;
	cin>>n;
	for(i=0;i<n;i++)
	{
		cin>>ball>>sc1>>sc2;
		if(ball>6)
		{
			sc1+=8*(ball-6)+27;
		}
		else
		{
			sc1+=(15-ball)*ball/2;
		}
		if(sc1>=sc2)
		{
			cout<<"Yes"<<endl;
		}
		else
		{
			cout<<"No"<<endl;
		}
	}
	return 0;
}

题解：这么长的题，其实它的意思是：如果还剩下多于6个球，那么每打一个红球打一个7分的彩球，得8*（n-6)分，再得2+3+4+5+6+7=27分。如果小于等于6，从7分的球开始算起，等差数列求和即可。