【解题思路】
对二叉树进行先序遍历,交换当前节点的左右子树。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode mirrorTree(TreeNode root) {
search(root);
return root;
}
public void search(TreeNode node)
{
if(node == null) return;
exchange(node);
search(node.left);
search(node.right);
}
public void exchange(TreeNode node)
{
if(node.left == null && node.right != null)
{
node.left = node.right;
node.right = null;
}
else if(node.left != null && node.right == null)
{
node.right = node.left;
node.left = null;
}
else if(node.left != null && node.right != null)
{
TreeNode p;
p = node.left;
node.left = node.right;
node.right = p;
}
}
}