Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length
of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = "Hello World", return 5.
思路:
找出最后一个字母的位置end,最后一个单词的第一个字母位置begin.长度len = end -begin.
注意到几种特殊情况:
1)空字符串,返回0
2)全部都是空格
3)最后几个字符是空格
#include <iostream>
using namespace std;
int getLethOfLastWord(string s)
{
int len = s.size();
if(len == 0) return 0;
while(len > 0 && s[len-1] == ' ')
{
len --;
}
int end = len;
while(len > 0 && s[len-1]!= ' ')
{
len--;
}
int begin = len;
int res = end - begin;
return res;
}
void main()
{
string s=" a bcd ";
int res = getLethOfLastWord(s);
printf("The last word length is %d.\n",res);
}
本文介绍了一种算法,用于确定给定字符串中最后一个非空格字符组成的单词的长度。该算法首先找到字符串中最后一个非空格字符的位置,并以此确定最后一个单词的起始位置,从而计算出单词的长度。

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