题目要求:
Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.
解题思路:利用位运算与(&)
难度:Easy
代码:
class Solution {
public:
int hammingWeight(uint32_t n) {
uint32_t k = 1;
int count = 0;
while (k)
{
if (k & n)
{
count++;
}
k = k << 1;
}
return count;
}
};
上面的代码简单的解决了这道题。