Search Range in Binary Search Tree
Description
Given a binary search tree and a range [k1, k2], return node values within a given range in ascending order.
/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
* @param root: param root: The root of the binary search tree
* @param k1: An integer
* @param k2: An integer
* @return: return: Return all keys that k1<=key<=k2 in ascending order
*/
public List<Integer> searchRange(TreeNode root, int k1, int k2) {
// write your code here
ArrayList<Integer> results = new ArrayList<>();
if(root == null){
return results;
}
List<Integer> left = searchRange(root.left, k1, k2);
List<Integer> right = searchRange(root.right, k1, k2);
if (root.val <= k2 && root.val >= k1){
results.add(root.val);
}
results.addAll(left);
results.addAll(right);
Collections.sort(results);
return results;
}
}