Description:
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
从一个数组中找到找到一对和为target的元素。并返回其下标。暴力解法如下:
class Solution {
public:
vector<int> twoSum(vector<int>& nums, int target) {
vector<int> v(2);
for(int i = 0; i < nums.size(); i ++) {
for(int j = i + 1; j < nums.size(); j ++) {
if(nums[i] + nums[j] == target) {
v[0] = i;
v[1] = j;
}
}
}
return v;
}
};